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// Copyright 2018-2021 the Deno authors. All rights reserved. MIT license.
/** * Builds all possible orders of all elements in the given array * Ignores equality of elements, meaning this will always reutrn the same * number of permutations for a given length of input. * * Example: * * ```typescript * const numbers = [ 1, 2 ] * const windows = permutations(numbers) * * console.assert(windows === [ *     [ 1, 2 ], *     [ 2, 1 ], * ]) * ``` */export function permutations<T>(array: Array<T>): Array<Array<T>> {  const ret: Array<Array<T>> = [];
  if (array.length === 0) {    return ret;  }
  // Heap Algorithm  function heapPermutations(k: number, array: Array<T>) {    const c = new Array<number>(k).fill(0);
    ret.push([...array]);
    let i = 1;
    while (i < k) {      if (c[i] < i) {        if (i % 2 === 0) {          const swapBuffer = array[0];          array[0] = array[i];          array[i] = swapBuffer;        } else {          const swapBuffer = array[c[i]];          array[c[i]] = array[i];          array[i] = swapBuffer;        }
        ret.push([...array]);
        c[i] += 1;        i = 1;      } else {        c[i] = 0;        i += 1;      }    }  }
  heapPermutations(array.length, [...array]);
  return ret;}