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export default function findMaxConsecutiveOnes(nums: number[]): number {    let m = 0;    let c = 0;    for (const v of nums) {        c = v ? c + 1 : 0;        m = Math.max(m, c);    }    return m;    // return nums.reduce(([c,m],v)=>{
    //     c=v?c+1:0    //     m=Math.max(m,c)    //     return [c,m]    // },[0,0])[1]}